How to do that should be clear theoretically. It was posted earlier on this blog. But if you do not remember any more or would like to look once again: the posts below are recommended.
The labyrinth here has a dimension between axes of 50 cm, the centre should get a diameter of 2 m, the central square also has sides of 2 m length, the whole diameter will thereby be 9 m.
We first stake off the 5 mean points on which later literally everything turns.
It is advisable to start with the internal cross, the only straight lines in the labyrinth; and then to form the remaining bends.
Doing so, the basis is created for the 8 following in parallel distance running arcs.
Here you can see/print/store/copy the drawing as a PDF file …
Here the dimension between axes of 50 cm was used. A radius of 50 cm for the smallest arc and for the biggest one a radius of 4.50 m. Therefore the whole diameter amounts to 9 m. For the size of the centre the 4-fold dimension between axes was applied. Thus the diameter of the centre is the same as the side length of the square formed by the 4 inflection points.
The labyrinth is scaleable in the size. If one wants to build, e.g., one with a dimension between axes of 1 m (what results 18 m for the whole diameter), one multiplies all measurements by 2.